Galuh A
13 September 2025 12:29
Galuh A
13 September 2025 12:29
Pertanyaan
matematika—translasi
matematika—translasi
3
1
RAYYA R
16 Oktober 2025 00:41
<p><strong><u>Soal 1</u></strong></p><p>y = 2x² - 8x + 3</p><p>y = 2(x² - 4x + 4) - 8 + 3</p><p>y = 2(x - <strong>2</strong>)² <strong>- 5</strong></p><p>Koordinat titik balik kurva : (2, -5)</p><p> </p><p>Koordinat titik balik kurva hasil translasi T(3, 5)</p><p>= (2, -5) + (3, 5)</p><p>= <strong>(5, 0)</strong></p><p> </p><p><strong><u>Soal 2</u></strong></p><p>y = 2x² - 15x + 26</p><p>xp = -b/2a = -(-15)/2.2 = 15/4</p><p>yp = 2(15/4)² - 15(15/4) + 26 = -17/8</p><p>P(xp, yp) = P(15/4, -17/8)</p><p> </p><p>y = 2x² - 7x + 5</p><p>xp = 7/4</p><p>yp = 2(7/4)² - 7(7/4) + 5 = -9/8</p><p>P'(7/4, -9/8)</p><p> </p><p>T(a, b) = P' - P </p><p>T(a, b) = (7/4, -9/8) - (15/4, -17/8)</p><p>T(a, b) = (-2, 1)</p><p> </p><p>2a - b = 2(-2) - 1 = <strong>-5</strong></p><p> </p>
Soal 1
y = 2x² - 8x + 3
y = 2(x² - 4x + 4) - 8 + 3
y = 2(x - 2)² - 5
Koordinat titik balik kurva : (2, -5)
Koordinat titik balik kurva hasil translasi T(3, 5)
= (2, -5) + (3, 5)
= (5, 0)
Soal 2
y = 2x² - 15x + 26
xp = -b/2a = -(-15)/2.2 = 15/4
yp = 2(15/4)² - 15(15/4) + 26 = -17/8
P(xp, yp) = P(15/4, -17/8)
y = 2x² - 7x + 5
xp = 7/4
yp = 2(7/4)² - 7(7/4) + 5 = -9/8
P'(7/4, -9/8)
T(a, b) = P' - P
T(a, b) = (7/4, -9/8) - (15/4, -17/8)
T(a, b) = (-2, 1)
2a - b = 2(-2) - 1 = -5
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