Tolong dibantu ya kak, terimakasih

<p>#cari mol dari massa yg diketahui untuk dimasukkan ke dalam mula' bereaksi dan sisa</p><p>* Rumus mol= gram/Ar atau Mr</p><p>- mol Mg= gram/Ar= 6/24= 0,25 mol</p><p>- mol MgO= gram/Mr= 10/40= 0,25 mol</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2Mg &nbsp; &nbsp; &nbsp; &nbsp;+ &nbsp; &nbsp; &nbsp; &nbsp;O_{2 &nbsp; &nbsp; &nbsp;}---&gt; &nbsp; &nbsp; &nbsp; &nbsp; 2MgO</p><p>m. &nbsp; &nbsp; &nbsp;0,25 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;0,125 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; -</p><p>r. &nbsp; &nbsp; &nbsp; &nbsp;0,25 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;<i><strong>0,125</strong></i> &nbsp; &nbsp; &nbsp; &nbsp;- &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 0,25 &nbsp; +</p><p>s. &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;0 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 0 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 0,25</p><p>&nbsp;</p><p>mol mula' oksigen didapatkan dari= 0,25×1÷2 = 0,125</p><p>mol pembatas reaksinya adalah 0,25</p><p>mol bereaksi oksigen= 0,25×1÷2 = 0,125</p><p>Jadi, massa untuk mol bereaksi oksigen= mol × Mr = 0,125×32 = 4 gram&nbsp;</p>